7[-6z-3+5(z+1)]=4z+2

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Solution for 7[-6z-3+5(z+1)]=4z+2 equation:


Simplifying
7[-6z + -3 + 5(z + 1)] = 4z + 2

Reorder the terms:
7[-6z + -3 + 5(1 + z)] = 4z + 2
7[-6z + -3 + (1 * 5 + z * 5)] = 4z + 2
7[-6z + -3 + (5 + 5z)] = 4z + 2

Reorder the terms:
7[-3 + 5 + -6z + 5z] = 4z + 2

Combine like terms: -3 + 5 = 2
7[2 + -6z + 5z] = 4z + 2

Combine like terms: -6z + 5z = -1z
7[2 + -1z] = 4z + 2
[2 * 7 + -1z * 7] = 4z + 2
[14 + -7z] = 4z + 2

Reorder the terms:
14 + -7z = 2 + 4z

Solving
14 + -7z = 2 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
14 + -7z + -4z = 2 + 4z + -4z

Combine like terms: -7z + -4z = -11z
14 + -11z = 2 + 4z + -4z

Combine like terms: 4z + -4z = 0
14 + -11z = 2 + 0
14 + -11z = 2

Add '-14' to each side of the equation.
14 + -14 + -11z = 2 + -14

Combine like terms: 14 + -14 = 0
0 + -11z = 2 + -14
-11z = 2 + -14

Combine like terms: 2 + -14 = -12
-11z = -12

Divide each side by '-11'.
z = 1.090909091

Simplifying
z = 1.090909091

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